Question

A large hydropower station has a head of 324 metre and an average flow of 1370 m³ / sec. The available hydraulic power from this station will be:

1. 4.35 MW
2. 4.15 MW
3. 4.47 MW
4. 4.73 MW

Answer 1

Correct Answer - Option 1 : 4.35 MW

Bernoulli’s equation:

Bernoulli’s equation is used to calculate the power output of the Hydropower plant.

Output power can be expressed as

\(P = 9.81\times 10^{-3} \times (\eta \ QWH )\) in Watts

Where,

η = Plant efficiency 

W = Density of water = 1000 Kg / m³

H = Mean water head in meters

Q = Discharge of water in m³ / sec

Calculation:

Given that,

H = 324 m

Q = 1370 m³ / sec

W = 1000 Kg / m³

If plant efficiency is not given in the question, then we take it as 100%

∴ η = 1 (For calculating capacity of plant)

The output power is

P = 9.81 x 10^-3 η QWH kW

P = 9.81 x 10^-3 x 1 x 1000 x 324 x 1370

∴ P = 4.35 MW