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The efficiency of radha is 50% more than that of shyam. Total work is 240 units.

Quantity I: Find the number of days radha alone will take to complete 200% of the work?

Quantity II: Find the number of days radha and shyam together will take to complete 50% of the work?


1. Quantity 1 > Quantity 2
2. Quantity 1 ≥ Quantity 2
3. Quantity 1 < Quantity 2
4. Quantity 1 ≤ Quantity 2
5. Quantity 1 = Quantity 2

1 Answer

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Best answer
Correct Answer - Option 1 : Quantity 1 > Quantity 2

Given:

Radha = 50% more efficient then shyam

Calculations:

The ratio of the efficiency of radha and shyam = 3 : 2

⇒ The total units of work = 240 units

⇒ the number of days, radha will take = 240 / 3

⇒ Number of days radha will take = 80 days

⇒ the number of days, shyam will take = 120 (∵ 240/2 = 120)

Quantity I:

200% of the work = 200% of 240

⇒ 480 units

The number of days, radha alone will take = 160 days (∵ 480/3 = 160)

Quantity II:

50% of the work = 120 units

⇒ The number of days, radha and shyam together will take to complete

⇒ 120 / 5

⇒ 24 days

∴ Quantity I > Quantity II

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