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In the given questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer.

I: 3x2 – 18x + 15 = 0

II : 4y2 – 84y + 320 = 0


1. x > y
2. x ≤ y
3. x = y or relation between x and y can not be determined.
4. x ≥ y
5. x < y

1 Answer

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Best answer
Correct Answer - Option 2 : x ≤ y

Calculation:

I: 3x2 – 18x + 15 = 0

⇒ 3x2 – 15x – 3x + 15 = 0

⇒ 3x × (x – 5) – 3 × (x – 5) = 0

⇒ (x – 5) × (3x – 3) = 0

⇒ x = 5, 1

II: 4y2 – 84y + 320 = 0

⇒ 4y2 – 20y – 64y + 320 = 0

⇒ 4y × (y – 5) – 64 × (y – 5) = 0

⇒ (y – 5) × (4y – 64) = 0

⇒ y = 5, 16

Comparison between x and y (via Tabulation):

Value of x

relation

Value of y

5

=

5

5

16

1

5

1

16

From the table, we can say, x ≤  y.

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