Question

Three men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will they take to complete the remaining work?
1. 4
2. 1
3. 3
4. 2

Answer 1

Correct Answer - Option 4 : 2

Given:

Three men can complete a piece of work in 6 days.

Formula used:

\(\frac{M_{1}\ × \ D_{1}}{W_{1}}\ =\ \frac{M_{2}\ × \ D_{2}}{W_{2}}\)

where M₁ = M₂ = number of man

D1  = D2 = number of days

W1 = W2 = part of work

Calculations: 

time taken = 6 days

part of work done in 1 day = 1/6

part work done in 2 days = (1/6) × 2 = 1/3

remaining work = 1 - 1/3 = 2/3

so ​​using above formula we get ​

\(\frac{3\ \times\ 2}{\frac{1}{3}}\ =\ \frac{6\ \times\ D_{2}}{\frac{2}{3}}\)

so D₂ = 2 days.

∴ the correct answer is 2 days.