Correct Answer - Option 4 : 8 : 1
Given:
The ratio of milk and water in the first vessel = 3 : 5
The ratio of milk and water in the second vessel = 3 : 2
The ratio of milk and water in the final mixture = 2 : 3
Concept used:
(New quantity of milk/New quantity of water) = (Quantity of milk taken from first vessel + Quantity of milk taken from the second vessel)/(Quantity of water taken from first vessel + Quantity of water taken from the second vessel)
Calculation:
Let the mixture from the two-vessel be mixed in the ratio x : y.
Quantity of milk taken from the first vessel = 3x/8
Quantity of water taken from the first vessel = 5x/8
Quantity of milk taken from the second vessel = 3y/5
Quantity of water taken from the second vessel = 2y/5
Then, {(3x/8) + (3y/5}/{(5x/8) + (2y/5)} = 2/3
⇒ {(15x + 24y)/40}/{(25x + 16y)/40} = 2/3
⇒ 3(15x + 24y) = 2(25x + 16y)
⇒ 45x + 72y = 50x + 32y
⇒ 50x – 45x = 72y – 32y
⇒ 5x = 40y
⇒ x/y = 8/1
∴ The first and second ratio is mixed in the ratio 8 : 1.