Correct Answer - Option 1 : 0.252 J
Concept:
The inductance of a solenoid is given by:
\(L = \frac{{{\mu _0}{N^2}A}}{l} \)
N = Number of turns
A = Area of the solenoid
l = length of the solenoid
Also, the energy stored by the inductor is given by:
\(E=\frac{1}{2}LI^2\)
Calculation:
Given that, inductance (L) = 0.126 H
Current (I) = 2 A
\(E = \frac{1}{2}L{I^2} = \frac{1}{2} \times 0.126 \times {2^2} \)
= 0.252 J
