Correct Answer - Option 1 : 1 and 2
Current (I) flows through a circular coil of radius R and only one turn, in a counter-clockwise direction.
Now, the magnetic field ‘H’ is given by
\(H = \frac{I}{{2\pi R}}\)
\( \Rightarrow H \propto \frac{1}{R}\)
Magnetic moment (m) is given by
m = I π R2 an ⇒ m ∝ R2
Therefore, the magnetic field at the centre is inversely proportional to the radius (R) and the magnetic moment (m) is directly proportional to R
2.