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Find the smallest number which when divided by 5, 6, 8 and 9 gives a remainder 3 in each case.

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Find the smallest number which when divided by 5, 6, 8 and 9 gives a remainder 3 in each case.
1. 360
2. 363
3. 370
4. 365
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Correct Answer - Option 2 : 363

Formula used - 

number = LCM + remainder in each case

Solution - 

LCM of (5, 6, 8, 9) = 360

⇒ Number = 360 + 3 = 363

∴ number = 363.

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