Question

Find the nature of the roots of the following quadratic equation. If real roots exist, find them.

3x² – 4√3x + 4 = 0

Answer 1

Given: 3x² – 4√3x + 4 = 0 

a = 3; b = -4√3; c = 4 

b² – 4ac = (-4√3)² – 4(3)(4) 

= 48 – 48 = 0 

∴ Roots are real and equal and they \(\frac{-b}{2a}\), \(\frac{-b}{2a}\)