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Find the nature of the roots of the following quadratic equation. If real roots exist, find them. 2x^2 – 6x + 3 = 0

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Find the nature of the roots of the following quadratic equation. If real roots exist, find them.

2x2 – 6x + 3 = 0

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Given: 2x2 – 6x + 3 = 0 

a = 2; b = -6; c = 3 

b2 – 4ac = (-6)2 – 4(2)(3) 

= 36 – 24 

= 12 > 0 

∴ The roots are real and distinct. They are

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