Seventh terms of AP
a7 = a + (7 - 1) d
a7 = a + 6d
seven times seventh term
= 7 (a + 6d)
= 7a + 4 d
fifth term of AP
a5 = a + (5 - 1)d
a5 = a + 42 d
five times fifth term
= 5(a + 4d)
= 5a + 20 d
According to question
7a + 42 d
∴ 5a + 20 d
2a = 22 d
a = -11 d...(1)
12th term of AP
a12 = a + 11 d
putting the value of equation (1)
a12 = -11 d + 11d
a12 = 0
Hence the twelth term of AP is 0
According to question
7a + 42 d = 5a + 20 d
2a = -22 d
a = -11 d...(1)
12th term of AP
a12 = a + 11 d
Putting the value of equation (1)
a12 = -11 d + 11 d
a12 = 0
Hence the twelth term of AP is a