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In a triangle ABC, the median to the side BC is of length 1/√(11 - 6√3) and it divides the angle A into angles 30° and 45°.

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In a triangle ABC, the median to the side BC is of length 1/√(11 - 6√3) and it divides the angle A into angles 30° and 45°. Find the length of the side BC.

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Let AD be the median to the base BC = a of ΔABC,  and let ∠ADC = θ, then

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