Statement I : [Fe(H2O)5 NO]SO4 is paramagnetic. Statement II : The Fe in [Fe(H2O)5NO]SO4 has three unpaired electrons.

Question

Read the following questions and answer as per the direction given below 

(a) Statement I is true; Statement Ii is true; Statement II is a correct explanation of Statement I. 

(b) Statement I is true; Statement II is true; Statement II is not the correct explanation of Statement I.

(c) Statement I is true; Statement II is false. 

(d) Statement I is false; Statement II is true.

Statement I : [Fe(H₂O)₅ NO]SO₄ is paramagnetic. 

Statement II : The Fe in [Fe(H₂O)₅NO]SO₄ has three unpaired electrons.

Answer 1

The correct option (a) Statement I is true; Statement Ii is true; Statement II is a correct explanation of Statement I. 

Explanation:

The oxidation number of Fe in the complex, 

[Fe(H₂O)₅NO]SO₄ is +1[NO has + 1 charge] 

Fe⁺ = [Ar] 3d⁶ 4s¹

NO⁺ causes pairing of 4s electron inside. 

Thus, the configuration is 3d⁷ and number of unpaired electrons = 3