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The equation of two light waves are `y_(1)=6cosomegat,y_(2)=8cos (omegat+phi)`.The ratio of maximum to minimum intensities produced by the supersposition of these waves will be-
A. `49:1`
B. `1:49`
C. `1:7`
D. `7:1`

1 Answer

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Answer:
`a_1=6` units
`a_2=8` units
`(I_(max))/(I_(min))=[(a_(1))/(a_(2))+1]^(2)/[(a_(1))/(a_(2))-1]^(2)=[(6)/(8)+1]^(2)/[(6)/(8)+1]^(2)rArr (I_(max))/(I_(min))=(49)/(1)`

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