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In a circus there are 10 cages for accommodating 10 animals out of these 4 cages are so small that five out of ten animals

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In a circus there are 10 cages for accommodating 10 animals out of these 4 cages are so small that five out of ten animals can not enter into them.In how many ways will it be possible to accommodate 10 animals in these 10 cages?

(a) 66400 

(b) 86400 

(c) 96400 

(d) 46900

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1 Answer

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Correct option: (b) 86400

Explanation:

arrangement of little animals that can not accommodate in small cage = 6P5 

arrangement of remaining 5 animals = 5P5 = 5!

∴ Total accomodations = 6P5 . 5P5 = 720 x 120 = 86400

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