
2(y2 + 1) = 5y
2y2 – 5y + 2 = 0
2y2 – 4y – y + 2 = 0
2y(y – 2) – 1(y – 2) = 0
(y – 2)(2y – 1) = 0
जब y – 2 = 0 तब जब y = 2
जब 2y – 1 = 0 तब y = 1/2
y = 2 लेने पर, \(\frac{3x+1}{x+1}\) = 2
3x + 1 = 2(x + 1)
3x + 1 = 2x + 2
3x – 2x = 2 – 1
x = 1
y = 1/2 लेने पर, \(\frac{3x+1}{x+1}=\frac{1}{2}\)
2(3x + 1) = x + 1
6x + 2 = x + 1
6x – x = 1 – 2
5x = -1
x = -1/5