Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
349 views
in Algebraic Expressions by (41.1k points)
closed by

निम्न के मान ज्ञात कीजिए।

(i) (99)3

(ii) (9.9)3

(iii) (10.4)3

(iv) (598)3

(v) (402)3

(vi) (1002)3

1 Answer

+1 vote
by (44.6k points)
selected by
 
Best answer

(i) (99)3 = (100 – 1)3

= (100) – (1)3 – 3 × 100 × 1(100 – 1)

= 1000000 – 1 – 30000+ 300 = 970299

(ii) (9.9)3 = (10 – 0.1)3

= (10)3 – (0.1)3 – 3 × 10 × 0.1(10 – 0.1)

= 1000 – 0.001 – 3(9.9)

= 1000 – 0.001 – 29.7 = 970.299

(iii) (10.4)3 = (10 + 0.4)3

= (10)3 + (0.4)3 + 3 × 10 × 0.4(10 + 0.4)

= 1000+ 0.064 + 12(10.4)

= 1000 + 0.064 + 124.8 =1124.864

(iv) (598)3 = (600-2)3

= (600)3 – (2)3 – 3 × 600 × 2(600 – 2)

= 216000000 – 8-21,60,000 + 7200

=21,38,47,192

(v) (402)3 = (400 + 2)3

= (400)3 + (2)3 + 3 × 400 × 2(400 + 2)

= 64000000 + 8 + 960000 + 4800

= 64964808

(vi) (1002)3 = (1000 + 2)3

= (1000)3 + (2)3 + 3 × 1000 × 2(1000 + 2)

= 1000000000 + 8+ 6000000 + 12000

= 1006012008

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...