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Q.The particle position as a function of time is given as x = 5t ^ 2 - 9t + 3 Find out the minimum value of position co-ordinate.

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x = 5t ^ 2 - 9t + 3

= 5(t^2-9/5t+3/5)

=5{t^2-2×t×9/10+(9/10)^2} -81/20+3

=5(t-9/10)^2-21/20
So minimum value of x will be obtained when t=9/10

Hence minimum value of the position coordinate will be

x=21/20=-1.05

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