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पाश्वकित चित्र में, AB = AC और ∠DAB = ∠CAD, तो क्या ΔACD और ΔABD सर्वांगसम हैं? यदि हैं तो क्यों?

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ΔACD तथा ΔABD में,

AC = AB

∠CAD = ∠DAB

तथा AD उभयनिष्ठ है। (SAS)

ΔACD = ΔABD

क्योंकि जिस त्रिभुज की दो भुजा और उनके बीच का कोण दूसरे त्रिभुज के दो भुजाओं और उनके बीच के कोण के अलग-अलग बराबर होते हैं, वे त्रिभुज सर्वांगसम होते हैं।

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