Question

Given below are the quantum numbers for 4 electrons.

A. n = 3, l = 2, m₁ = 1, m_s = + 1/2

B. n = 4, l = 1, m₁ = 0, m_s = + 1/2

C. n = 2, l = 2, m₁ = 1, m_s = + 1/2

D. n = 3, l = 2, m_s = 1, m_s = + 1/2

The correct order of increasing energy is : 

(A) D < B < A < C 

(B) D < A < B < C 

(C) B < D < A < C 

(D) B < D < C < A

Answer 1

(B) D < A < B < C 

Energy order of subshell decided by (n+λ) rule.