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When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary. If the force F1 is now removed than the acceleration of the particle is 

(A) (F1 / m) 

(B) (F1F2 / m) 

(C) [(F2 – F3) / m] 

(D) (F2 / m)

1 Answer

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Best answer

Correct option: (A) (F1 / m)

Explanation:

F2 and F3 are perpendiculars.

To keep particle
stationary.

|F2 + F3| = |F1|

i.e. |F1| is magnitude of resultant of F2 and F3.

hence when F1 is removed,

a = (F1 / m)

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