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A force of 7N, making an angle θ with the horizontal, acting on an object displaces it by 0.5 m along the horizontal direction.

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A force of 7N, making an angle θ with the horizontal, acting on an object displaces it by 0.5 m along the horizontal direction. If the object gains K.E. of 2J, what is the horizontal component of the force? 

(A) 2N 

(B) 4N 

(C) 1N 

(D) 14N

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Correct option: (B) 4N

Explanation:

Kinetic energy = Fd cosθ

2 = 7 × 0.5 × cosθ

cosθ = 0.571

Horizontal component = F cosθ = 7 × 0.571 = 3.99 N   

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