Question

A network of six identical capacitors, each of value C is made as shown in figure. Equivalent capacitance between points A and B is 

(A) (C/4) 

(B) (3C/4) 

(C) (4C/3) 

(D) 3C

Answer 1

The correct option (C) (4C/3)

Explanation:

Given network can be drawn as shown

 it can be redrawn as:

on further reduction, circuit becomes

for upper and lower half C & 2C are in series, hence equivalent is

[(1/C) + (1/2C)]⁻¹ = (2/3)C

 here (2/3)C & (2/3)C are in parallel. hence

 Final capacitance = (2/3)C + (2/3)C = (4/3) C