Question

Point charges of +2μC,+4μC,−6μC and +8μC are placed at the corners A,B,C and respectively of a square ABCD of side 0.2 m. Calculate the resultant force on the charge at D.

Answer 1

Given four charges placed at corners A, B, C and D of square of side 0.2m.

AD = CD = 0.2m

BD = \(\sqrt{(0.2)^2 + (0.2)^2​}\)

= 0.283m

So, force on +8μC due to charge at A 

Now, net force = Resultant of F′ and F2​