A dice is rolled twice. So no. Of elements in sample space = 36
i.e. {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)(2,1),........(6,6)}
1) sum = 6 and 4 has occurred on one of dice= {(2,4),(4,2)}
Probability= Possible outcome/Total outcome = 2/36
= 1/18
2) 3 has occurred one of dice and sum 4 cases = {(1,3),(3,1)}
Probability = 2/36
= 1/18