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The magnetic field at a point x on the axis of a small bar magnet is equal to the at a point y on the equator of the same magnet. The ratio of the distances of x and y from the centre of the magnet is 

(a) 2–3 

(b) 2–(1/3) 

(c) 23 

(d) 2+(1/3)

1 Answer

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Best answer

The correct option (d) 2+1/3

Explanation:

On the axis, B1 = (2M/x3)

On the equator, B2 = (M/y3)

as B1 = B2

(2M/x3) = (M/y3)

∴ (x/y)3 = 2

(x/y) = 2(1/3)

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