Correct option (C) only II and III are true
Explanation:
P(sin2 x) = P(cos2 x)
P(sin2 x) = P(1 – sin2 x)
P(x) = P(1 – x) ∀ x ∈ [0, 1]
Differentiable both sides w.r.t. x
P'(x) = – P'(1 – x)
So P '(x) is symmetric about point x = 1/2
So P '(x) has highest degree odd
⇒ P(x) has highest degree even