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Find the equation of a circle passing through the origin if the line pair, xy – 3x + 2y – 6 = 0 is orthogonal to it. If this circle is orthogonal to the circle x2 + y2 – kx + 2ky – 8 = 0 then find the value of k.

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 Let the equation of circle be

(x + 2) (y – 3) = 0

The centre is point of intersection of these two lines 

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