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Energy of 10 non rigid diatomic molecules at temperature T is : 

(1) \(\frac{7}{2}\ \text RT\)

(2) 70 KB

(3) 35 RT 

(4) 35 KB

1 Answer

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Best answer

Correct option is : (4) 35 KBT

Degree of freedom(f) = 5 + 2(3N – 5) f = 5 + 2(3 × 2 –1) = 7 

energy of one molecule = \(\frac{f}{2}K_BT\) 

energy of 10 molecules \(=10\left(\frac{f}{2}K_BT\right)=10\left(\frac{7}{2}K_BT\right)=35\ K_BT\)   

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