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What do you understand by angle of friction and angle of repose? Prove that in the situation of limiting friction the values of both these angles are same.

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Angle of Friction : In situation of limiting friction, the angle between normal reaction R and resultant P of normal reaction R and limiting friction f(s), is called the angle of friction. In figure it is shown by α. 

In figure, a block A is shown placed on a rough surface and an external force F is acting on it to move it. As a reaction of F, there will be two forces. 

1. Normal reaction R which balances the weight mg of the block.

In situation of limiting friction,

2. Limiting friction force f(s) = µ(s). R parallel to surface of contact which is equal and opposite to applied force \(\vec F\). Resultant of both these reactions is P which makes an angle a with normal reaction R.

\(\therefore\ \tan\alpha = \frac{PR}{OR} = \frac{f(s)}{R} = \frac{\mu_s(R)}{R}\)

\(\tan\alpha =\mu_s\)

∴ Angle of friction

\(\alpha = \tan^{-1}(\mu_s)\)

Coefficient of Static Friction:

\(\therefore\ \mu_s = \tan\alpha\) 

Therefore, the tangent of angle of friction is called coefficient of static friction.

Magnitude of resultant force : This force is known as contact force. The value of contact force shown in figure is,

It magnitude of resultant force 

\(P = \sqrt{f_{(s)}^{2} + R^2\because \vec R\bot\overrightarrow{f_{(s)}}}\)

\(=\sqrt{(\mu_sR)^2 + R^2}\)

\(P = R\sqrt{1 + \mu_s^{2}}\)

Friction on an Inclined Plane-Angle of Repose:
The angle between inclined plane and horizontal, when any block placed on the plane remains at rest, is called angle of repose.

In figure, a block of mass M is placed on an inclined plane of angle of inclination f3. The forces acting on the block are shown in the diagram. 

Friction on an Inclined Plane-Angle of Repose:

Free body diagram of block

Equations of motion,

Mg cos ß = R .......(1)

and Mg sin ß = µs.R .......(2)

Free body diagram of block

On dividing equation (2) by (1), we have

\(\frac{Mg\sin\beta}{Mg\cos\beta} = \frac{\mu sR}{R}\) 

or tan ß = µs ......(3)

but tan α = µs ........(4)

where α is angle of friction.

From equations (3) and (4), we have

ß = α

i. e, Angle of repose = Angle of friction

If the angle of inclination of the plane ≤ß, then the block placed on the plane will remain at rest. But when angle of inclination of the plane > ß, then the block will start slipping on the plane in downward direction.

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