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A given volume of O2 gas diffuses in 224 seconds. Under identical conditions same volume of a mixture of O2 and another

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A given volume of O2 gas diffuses in 224 seconds. Under identical conditions same volume of a mixture of O2 and another unknown gas diffuses in 234 seconds. If the mixture contains 80% O2, calculate the molecular mass of the unknown gas. 

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1 Answer

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Mixture contains O2 = 80% 

Unknown gas = 20%

Suppose,

Molecular mass of unknown gas = m

According to Graham’s law

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