Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.0k views
in Physics by (71.7k points)

A mild steel bar of 10 mm in diameter and 100 mm in gauge length is tested under tension. A tensile force of 10 kN produces an axial strain = 610μs, lateral strain = 180μs. Determine E and v for mild steel.

1 Answer

+1 vote
by (71.0k points)
selected by
 
Best answer

Tensile force, P = 10,000 N 

 Sample diameter, d = 10 mm

 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...