Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
587 views
in Physics by (64.2k points)

The potential difference, VC, across a 3 Farad parallel-plate capacitor whose plates have radius R = 2 cm varies with time and is given by VC(t) = at, with a = 10 V/s. What is the magnitude of the magnetic field (in microT) between the plates of the capacitor a distance R from the center? 

1 Answer

+1 vote
by (61.3k points)
selected by
 
Best answer

We know from Ampere's Law (with J = 0 inside the capacitor) that

 

If I choose a loop of radius R within the capacitor then ΦE = EπR2 and

where I have used E = Q/(ε0A), A = πR2, and I = dQ/dt. Solving for B gives

where I used Q = CV which implies that dQ/dt = C dV/dt with dV/dt = a.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...