Question

The potential energy of particle of mass 0.1kg, moving along x-axis, is given by U=5x(x-4)J where x is in meters. It can be concluded that 

(A) The particle is acted upon by a constant force. 

(B) The speed of the particle is maximum at x=2m 

(C) The particle executes simple harmonic motion 

(D) The period of oscillation of the particle is π /5 s

Answer 1

Correct Option (B, C, D)

Explanation:

P.E. minimum at x = 2 m 

Force is linear function of x with negative slope.