Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.6k views
in Physics by (80.0k points)

Two tuning forks of frequencies 350 Hz each move relative to a stationary observer. One fork moves away from the observer, while the other moves toward him at the same speed. The observer hears beats of frequency 4 Hz. Find the speed of each tuning fork relative to the stationary observer. Velocity of sound in air = 340 m s–1.

1 Answer

+1 vote
by (76.2k points)
selected by
 
Best answer

The apparent frequency of the tuning fork coming towards the stationary observer is

where vs = speed of the tuning fork. 

The apparent frequency of the tuning fork going away from the observer is

Since vs is positive, the positive root of the above equation is

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...