Question

A ring of mass m and radius R rolls on a horizontal rough surface without slipping due to an applied force ‘F’. The friction force acting on ring is : – 

(A) F / 3

(B) 2F / 3

(C) F / 4

(D) Zero

Answer 1

Correct option: (D) Zero

Explanation:

F + f = ma .... (1)

Also ; FR – fR = 1 a/R

F – f = ma .... (2) [ I = mR² ]

From (1) & (2)

f = 0.