Question

Calculate for 0.01 N solution of sodium acetate (i) Hydrolysis constant (ii) Degree of hydrolysis (iii) pH Given K_a of CH₃COOH = 1.9 × 10^–5.

Answer 1

(iii) [OH^–] from NaOH, a strong base = Ch = 0.01 × 2.29 × 10^–4 = 2.29 × 10^–6 M pOH = 5.64 

pH = 14 – 5.64 = 8.36