Question

The domain of sin^-1[log₃(x/3)]  is

(a) [1,9]

(b) [-1,9]

(c) [-9,1]

(d) [-9,-1].

Answer 1

(a) : If y = sin^–1x, then –1 ≤ x ≤ 1

Therefore, -1 ≤ log₃(x/3) ≤ 1[as y sin^-1[log₃(x/3)]]

=> 1/3 ≤ x/3 ≤ 3¹

=> 1 ≤ x ≤ 9