Resistance between A and C (Fig. 1.17).

= 6 || 3 = 2 Ω
Resistance of branch ACD = 18 + 2 = 20 Ω
Now, there are two parallel paths between points A and D of resistances 20 Ω and 5 Ω.
Hence, resistance between A and D = 20 || 5 = 4 Ω
∴ Resistance between A and B = 4 + 8 = 12 Ω
Total circuit current = 60/12 = 5 A
Current through 5 Ω resistance = 5 x 20/25 = 4A
Current in branch ACD = 5 x 5/25 = 1A
∴ P.D. across 3 Ω and 6 Ω resistors = 1 × 2 = 2V
P.D. across 18 Ω resistors = 1 × 18 = 18V
P.D. across 5 Ω resistors = 4 × 5 = 20V
P.D. across 8 Ω resistors = 5 × 8 = 40V