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The sum of three consecutive integers is 39. Which of the following is the largest among the three?
(a) 12 (b) 15
(c) 13 (d) 16
(e) None of these

1 Answer

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Best answer

(e) Let the three consecutive integers be x, x + 1 and x + 2 

According to the question,

 x + x + 1 + x + 2 = 39 

or, 3x + 3 = 39 

or, 3x = 39 – 3 = 36 

or, x = 36 /3 = 12 

Required largest number = x + 2 = 12 + 2 = 14

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