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There are three pillars X, Y and Z of different heights. Three spiders A, B and C start to climb on these pillars simultaneously. In one chance, A climbs on X by 6 cm but slips down 1 cm. B climbs on Y by 7 cm but slips down 3 cm. C climbs on Z by 6.5 cm but slips down 2 cm. If each of them requires 40 chances to reach the top of the pillars, what is the height of the shortest pillar? 

(a) 161 cm 

(b) 163 cm 

(c) 182 cm 

(d) 210 cm

1 Answer

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Best answer

Correct option (b) 163 cm

Explanation:

Pillar X: In one chance, A climbs on X by 6 cm but slips down 1 cm. 

Hence, in one chance A climbs 6 – 1 = 5 cm. 

Height attained after 39 chances = 39 × 5 = 195 cm

Thereafter in the 40th and last chance it will climb 6cm to reach the top. 

So, height of pillar X = 195 + 6 = 201 cm

Pillar Y: In one chance, B climbs on Y by 7cm but slips down 3cm. 

Hence, in one chance B climbs 7 – 3 = 4 cm. 

Height attained after 39 chances = 39 × 4 = 156 cm 

Thereafter in the 40th and last chance it will climb 7 cm to reach the top. 

So, height of pillar Y = 156 + 7 = 163 cm

Pillar Z: In one chance, C climbs on Z by 6.5 cm but slips down 2 cm. 

Hence, in one chance C climbs 6.5 – 2 = 4.5 cm. 

Height attained after 39 chances = 39 × 4.5 = 175.5 cm

Thereafter in the 40th and last chance it will climb 6.5 cm to reach the top. 

So, height of pillar Z = 175.5 + 6.5 = 182 cm 

So, height of the shortest pillar (i.e. pillar Y) = 163 cm

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