Join Sarthaks eConnect Today - Largest Online Education Community!
0 votes
8 views
asked ago in Mathematics by (18.9k points)

Solve the system of equations:

2/x + 3/y + 10/z = 4

4/x - 6/y + 5/z = 1

6/x + 9/y - 20/z = 2

1 Answer

+1 vote
answered ago by (21k points)
selected ago by
 
Best answer

Let 1/x = p, 1/y = q and 1/z = r,  then the given equations become 

2p + 3q + 10r = 4, 4p − 6q + 5r = 1, 6p + 9q − 20r = 2 

This system can be written as AX = B, where

Thus, A is non-singular. Therefore, its inverse exists. Therefore, the above system is consistent and has a unique solution given by X = A −1

Cofactors of A are 

A11 = 120 − 45 = 75,

A12 = − ( − 80 − 30) = 110, 

A13 = (36 + 36) = 72, 

A21 = − ( − 60 − 90) = 150, 

A22 = ( − 40 − 60) = − 100, 

A23 = − (18 − 18) = 0, 

A31 = 15 + 60 = 75, 

A32 = − (10 − 40) = 30, 

A33 = − 12 − 12 = − 24

Happy Diwali Wishes

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

Categories

...