Question

From the top of a tower, a stone is thrown up and it reaches the ground in time t₁. A second stone is thrown down with the same speed and it reaches the ground in time t₂. A third stone is released from rest and it reaches the ground in time t₃.

(a) t₃ = 1/2 (t₁ + t₂)

(b) t₃ = √ t₁t₂

(c) 1/t₃ = 1/t₂ - 1/t₁

(d) t₃² = t₁² - t₂²

Answer 1

Correct answer is: (b) t₃ = √ t₁t₂