Question

Three particles A, B and C are thrown from the top of a tower with the same speed. A is thrown straight up, B is thrown straight down and C is thrown horizontally. They hit the ground with speeds v_A, v_B and v_C respectively.

(a) v_A = v_B = v_C

(b) v_B > v_C > v_A 

(c) v_A = v_B > v_C 

(d) v_A > v_B = v_C

Answer 1

Correct answer is: (a) v_A = v_B = v_C

The increase in kinetic energy = the loss in potential energy. This is the same for all three.