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Find the area bounded by the curve x^2 = 4y and the straight line x = 4y – 2.

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in Integrals calculus by (38.6k points)

Find the area bounded by the curve x2 = 4y and the straight line x = 4y – 2.

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Best answer

Given curves are x2 = 4y and x = 4y – 2

Hence, the required area

 = 9/8 sq.u. 

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