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in Integrals calculus by (37.0k points)

Find the area enclosed between the parabolas y2 – 2y + 4x + 5 = 0 and x2 + 2x – y + 2 = 0.

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Best answer

Given curves are y2 – 2y + 4x + 5 = 0 and x2 + 2x – y + 2 = 0 

(y – 1)2 = – 4(x + 1) and (x + 1)2 = (y – 1)

Hence, the required area

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