Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.0k views
in Integrals calculus by (37.0k points)

Find the area enclosed between the smaller arc of the circle x2 + y2 – 2x + 4y – 11 = 0 and the parabola y = – x2 + 2x + 1 – 2√3.

1 Answer

+1 vote
by (38.6k points)
selected by
 
Best answer

Given curves are 

x2 + y2 – 2x + 4y – 11 = 0 

and y = –x2 + 2x + 1 – 2√3 

(x – 1)2 + (y + 2)2 = 16 

and y + 2(√3 – 1) = – (x – 1)2 

Hence, the required area

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...