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In the circuit shown, the symbols have their usual meanings. The cell has emf E. X is initially joined to Y for a long time. Then, X is joined to Z. The maximum charge on C at any later time will be

(a)  /RLC

(b) R/2LC

(c)  LC/2R

(d) LC/2R

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Correct Answer is: (d) LC/2R

When X is joined to Y, in the steady state, the current is imax/R .The maximum charge can be obtained from the relation Qmax = imax √LC 

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