Answer is (A) (1/2, 1/2)
It is given that
y(x – 2)(x – 3) = x + 6
At y-axis, we know that x = 0.
Therefore,
y(−2)(−3) = 0 + 6
Now, y(x2 – 5x + 6) = x + 6
⇒ y = (x + 6)/(x2 - 5x + 6)
Differentiating w.r.t. x, we get

Therefore, the equation of normal is
y – 1 = −1(x – 0)
That is, y + x −1 = 0 or y + x = 1.
Thus, the normal to the given curve line passes through (1/2, 1/2)