Question

The integral ∫(sin²xcos²x)/(sin³x + cos³x)²)dx  equal to

(A) 1/(1 + cot³x) + c

(B) - 1/(3(1 + tan³x)) + c

(C) sin³x/(1 + cos³x) + c

(D) - cos³x/(3(1 + sin³x)) + c

Answer 1

Answer is (B) - 1/(3(1 + tan³x)) + c

Now put tanx = t. Then sec²xdx = dt.